Tuesday

September 16, 2014

September 16, 2014

Posted by **Lueshelle** on Tuesday, April 24, 2012 at 8:56am.

- intermediate algebra -
**Damon**, Tuesday, April 24, 2012 at 10:15am4^-2 = 1/4^2 = 1/16

x^-2 = 1/x^2

(y^-2)^-2 = (1/y^2)^-2= = y^4

so

y^4/(16 x^2)

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