Posted by John on Tuesday, April 24, 2012 at 3:00am.
Let F-Raoul be the force exerted by Raoul.
Consider the direction perpendicular to Rory's direction,
There is no nett force in that direction as there is no movement along it.
F-Raoul Cos(40º) = 400 N * Cos(60º) ------> F-Raoul = 261 N
Nett force in Rory's direction = 800 N - 261 N * Sin(40º) - 400 N * Sin(60º).
You just apply F = m*a to find the acceleration.
In the case of resolving the force perpendicular to Rory's direction, isnt it suppose to be F-Raoul cos(50º) = 400 cos(30º) ?
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