posted by shankar .
A straight highway leads to the top of the base of a 50 meter tall tower. Frm the top of the tower, if yhe angles of depression of two cars on the road are 30° and 60° , then the distence between the tow cars is ................meter.
We form 2 rt. triangles with a common ver. side:
Y = 50 m. = Ver. side.
X1 = hor. side of larger triangle(30 Deg).
X2 = hor. side of smaller triangle(60 Deg).
tan30 = Y/x1 = 50/X1.
X1 = 50/tan30 = 86.6 m.
X2 = 50/tan60 = 28.9 m.
d = X1 - X2 = 86.6 - 28.9 = 57.7 m. =
The distance between cars.