How many moles of O2 are needed for the complete combustion of 3 moles of CH4?
Write and balance the equation, then use the coefficients.
CH4 + 2O2 ==> CO2 + 2H2O
The equation tells you that 1 mol CH4 requires 2 mols O2; therefore, 3 mols CH4 will require......mols O2.
To determine the number of moles of O2 needed for the complete combustion of 3 moles of CH4 (methane), we need to examine the balanced chemical equation for the combustion reaction of CH4.
The balanced equation is:
CH4 + 2O2 -> CO2 + 2H2O
From the balanced equation, we can see that for every 1 mole of CH4, we need 2 moles of O2. Therefore, to calculate the number of moles of O2 needed for 3 moles of CH4, we can set up a ratio:
3 moles CH4 : 2 moles O2
Now, plug in the values into the ratio:
3 moles CH4 x (2 moles O2 / 1 mole CH4) = 6 moles O2
Therefore, 6 moles of O2 are needed for the complete combustion of 3 moles of CH4.
To determine the number of moles of O2 needed for the complete combustion of 3 moles of CH4, we start by determining the balanced chemical equation for the combustion of CH4.
The balanced chemical equation is:
CH4 + 2O2 -> CO2 + 2H2O
From the equation, we can observe that 1 mole of CH4 reacts with 2 moles of O2.
Therefore, for the combustion of 3 moles of CH4, we would need 2 moles of O2 for every mole of CH4.
Since we have 3 moles of CH4, we would require 3 x 2 = 6 moles of O2.
Therefore, 6 moles of O2 are needed for the complete combustion of 3 moles of CH4.