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March 3, 2015

Posted by **Tabby** on Monday, April 23, 2012 at 8:23pm.

Please help me - I have no idea what to do or even where to start!

- Resultant Force? -
**Damon**, Monday, April 23, 2012 at 8:50pmprobably easier for you to do this on x, y axis system

First find x and y components of first force (15deg above x axis)

F1x = 35 cos 15

F1y = 35 sin 15

now the second force(90-55) = 35 below -x axis)

F2x = -75 cos 35

F2y = -75 sin 35

now add components

Fx = 35 cos 15 -75 cos 35 = -27.6

Fy = 35 sin 15 -75 sin 35 = -34.0

F^2 = Fx^2+Fy^2

so F = 43.7 in magnitude

tan theta = Fy/Fx = -43/-27.6

in quadrant 3 because both are negative

so theta = 57.3 deg below -x axis

or 57.3 deg south of west

or 90-57.3 = 32.7 deg west of south

- Resultant Force? -
**Help Please?**, Monday, April 23, 2012 at 8:57pmAh, thank you so much! You're a lifesaver! Thank you and God bless you for taking the time to help!

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