February 25, 2017

Homework Help: physics

Posted by Anonymous on Monday, April 23, 2012 at 5:23pm.

A proton moves in a constant electric field E
from point A to point B. The magnitude
of the electric field is 4.2 x10^4 N/C; and it is directed as shown in the drawing, the
direction opposite to the motion of the proton. If the distance from point A to point B
is 0.18 m, what is the change in the proton's electric potential energy, EPEA – EPEB?

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