Posted by **Julie** on Monday, April 23, 2012 at 2:35pm.

A hot iron horseshoe (mass = 0.43 kg), just forged (Fig. 14-16), is dropped into 1.60 L of water in a 0.26 kg iron pot initially at 20°C. If the final equilibrium temperature is 26°C, estimate the initial temperature of the hot horseshoe.

Could someone please help me out with how to do this. Thank you!

The sum of the heats gained is zero.

heatgainedbyIron+heatgainedbyWater=0

.43*specheatiron*(36-Ti)+1.60*specheatwater*(26-20)=0

solve for Ti

T is final iron temp

a liter of water is a kilogram

heat out of horseshoe = heat into water + heat into pot

.43 Ciron(T-26) = 1.6 Cwater (6 ) + .26 Ciron(6)

I get 1348.26 degrees in Celsius which does not make any sense to me and its wrong, so could someone please help. Thank you!

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