Posted by **John** on Monday, April 23, 2012 at 12:57pm.

Find the equation of the tangent line to the curve y=e^2x + 4x at the point (0,1)

- calculis -
**Reiny**, Monday, April 23, 2012 at 12:59pm
dy/dx = 2 e^(2x) + 4

at the point (0,1)

dy/dx = 2e^0 + 4

= 6

y = 6x + 1

since (0,1) is the y-intercept we can just state the answer.

btw, one would expect a student to correctly spell the subject he/she is studying.

## Answer This Question

## Related Questions

- Calculus AB - Could someone please help me with these tangent line problems? 1) ...
- Calculus AB - Sorry but I've got a lot of problems that I don't understand. 1) ...
- calculus - Consider the curve defined by 2y^3+6X^2(y)- 12x^2 +6y=1 . a. Show ...
- Calculus - If F(x)=x^3−7x+5, use the limit definition of the derivative to...
- Help Calc.! - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+y^2+1...
- please help; calc - original curve: 2y^3+6(x^2)y-12x^2+6y=1 dy/dx=(4x-2xy)/(x^2+...
- AP AB Calculus - Linear approximation: Consider the curve defined by -8x^2 + 5xy...
- calculus - Consider line segments which are tangent to a point on the right half...
- Calculus - Please help this is due tomorrow and I don't know how to Ive missed a...
- calc - for the parametric curve defined by x=3-2t^2 and y=5-2t ...sketch the ...

More Related Questions