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March 25, 2017

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Find the equation of the tangent line to the curve y=e^2x + 4x at the point (0,1)

  • calculis - ,

    dy/dx = 2 e^(2x) + 4

    at the point (0,1)
    dy/dx = 2e^0 + 4
    = 6

    y = 6x + 1

    since (0,1) is the y-intercept we can just state the answer.

    btw, one would expect a student to correctly spell the subject he/she is studying.

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