Posted by **John** on Monday, April 23, 2012 at 12:57pm.

Find the equation of the tangent line to the curve y=e^2x + 4x at the point (0,1)

- calculis -
**Reiny**, Monday, April 23, 2012 at 12:59pm
dy/dx = 2 e^(2x) + 4

at the point (0,1)

dy/dx = 2e^0 + 4

= 6

y = 6x + 1

since (0,1) is the y-intercept we can just state the answer.

btw, one would expect a student to correctly spell the subject he/she is studying.

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