Sunday

August 31, 2014

August 31, 2014

Posted by **Amber** on Monday, April 23, 2012 at 12:38pm.

Find the angular momentum of the system

about their center of mass.

Answer in units of J · s

Find the total kinetic energy of the system.

Answer in units of J

- Physics. PLEASE HELP!! -
**Elena**, Monday, April 23, 2012 at 4:07pmDistance between the skaters is d, frequency is n =1/7.6 s^-1

Location of the center of mass

of the second skater of mass m2 is

x1 = d •m2/(m1+m2),

x2 = d - x1,

Moment of inertia of the system is

I= I1 +I2 =

= m1•x1^2 + m2•x2^2.

Angular momentum is

L = I•ω= I•2•π•n.

KE = I• ω^2/2 = I•(2•π•n)^2/2.

Check your given data. It seems to me that the distance 4.6 m is too much if the “skaters hold hands”. Moreover, the mass m1 = 15 kg is improbable for skater (this is the mass of the child of three).

**Related Questions**

Physics. PLEASE HELP!! - Two ice skaters hold hands and rotate, making one ...

physics - In the figure, two skaters, each of mass 58.0 kg, approach each other ...

Physics - two skaters, each of mass 55 kg, approach each other along parallel ...

Physics - Two identical ice skaters are holding onto opposite ends of a very ...

physics - Two ice skaters have masses m1 and m2 and are initially stationary. ...

Physics - Two ice skaters have masses m1 and m2 and are initially stationary. ...

Physics - Two ice skaters have masses m1 and m2 and are initially stationary. ...

Physics - Two ice skaters, with masses of 30kg & 85 kg are at the center of a ...

physics(IMPORTANT) - Two skaters of mass m1=50 kg and m2=70 kg are standing ...

Physics(IMPORTANT) - Two skaters of mass m1=50kg and m2=70kg are standing ...