Posted by Amber on Monday, April 23, 2012 at 12:38pm.
Distance between the skaters is d, frequency is n =1/7.6 s^-1
Location of the center of mass
of the second skater of mass m2 is
x1 = d •m2/(m1+m2),
x2 = d - x1,
Moment of inertia of the system is
I= I1 +I2 =
= m1•x1^2 + m2•x2^2.
Angular momentum is
L = I•ω= I•2•π•n.
KE = I• ω^2/2 = I•(2•π•n)^2/2.
Check your given data. It seems to me that the distance 4.6 m is too much if the “skaters hold hands”. Moreover, the mass m1 = 15 kg is improbable for skater (this is the mass of the child of three).
Related Questions
Physics. PLEASE HELP!! - Two ice skaters hold hands and rotate, making one ...
Physics - Two identical ice skaters are holding onto opposite ends of a very ...
Physics - two skaters, each of mass 55 kg, approach each other along parallel ...
Physics - Two ice skaters, with masses of 30kg & 85 kg are at the center of ...
Physics - Two ice skaters have masses m1 and m2 and are initially stationary. ...
Physics - Two ice skaters have masses m1 and m2 and are initially stationary. ...
physics - Two ice skaters have masses m1 and m2 and are initially stationary. ...
physics - In a skating stunt known as crack-the-whip, a number of skaters hold ...
Physics - A trapeze artist weighs 8.00 x 10^2 N. The artist momentarily held to ...
physic - two figure skaters, one weighting 625N and the other 725N,push off ...
For Further Reading
