Posted by Hannah on Monday, April 23, 2012 at 12:17pm.
I started to write this a couple of days ago when I saw this post but didn't. Frankly, I thought both professor Reiny and professor Pursley misinterpreted the question. I still think so. I don't think it has anything to do with e. I believe you meant
[(0.50-x)/x] = 3.20E-1 which I would rewrite as
0.320 = (0.50-x)/x, then
0.320x = 0.50-x
1.320x = 0.50 and
x = 0.50/1.320
x = ?
Ok thank you the way you have it is exactly the way that it was stated on my homework. The only problem is that I realized that I had the typed the wrong number. It was suppose to be the same equation but with 2.49e-1 instead 3.20e-1. I understand everything except how did you get 1.320?
0.320 = (0.50-x)/x, then
0.320x = 0.50-x
0.320x = 0.50 -x
add x to both sides.
0.320x + x = 0.50 -x +x
0.320x + 1x = 0.50
1.320x = 0.50 and
x = 0.50/1.320.
1.320x = 0.50 and
x = 0.50/1.320
Thank you.
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