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March 29, 2017

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You dissolve 6.55 g of potassium nitrate in enough water to make a 250. ML solution.

1.What is the molarity of this solution?answer:0.0262

2.If you took out 15.0 mL of this solution, how many moles of potassium nitrate would you have?answer:0.393

3. What is the percent (m/v) of this solution?answer:0.0262

4.If the resulting solution has a density of 1.45 g/mL, what is the percent (m/m) of the solution?answer:0.0181

5.How does the freezing point of this solution compare with that of pure water?answer:should be lower

6.How does the boiling point compare?answer:it should be higher than that for pure water

7.If you added 1.25 L of additional water to this solution, what would the molarity of this new solution be?answer:.0432

  • Chemistry(Please Check) - ,

    4,5,6 look ok.
    1,2,and 3 I can't confirm.
    Show your work on those.
    I didn't check 7.

  • Chemistry(Please Check) - ,

    This is what I did..please check it

    1.P1V1=P2V2
    P=6.55/250=.0262

    2.V=P*V1/V2
    P=6.55*15.0/250=.393

    3.P=PV2V
    PP=6.55/250=.0262

  • Chemistry(Please Check) - ,

    1, 2, and 3 are NOT gas law problems. They are concentration problems.
    1.
    mols = grams/molar mass
    Then M = mols/L soln

    2.
    mols = M x L = ?

    3. You have 6.55 g in 250 mL. Convert this to g/100 for % m/v.

  • Chemistry(Please Check) - ,

    DID I DO IT RIGHT NOW

    1.M=6.55*1mol/101gn=.065
    .065/250=.260
    2.m=6.55g*15.0=.89 so this mean I need to use the full 250ml
    3.6.55/250*100=2.62

  • Chemistry(Please Check) - ,

    correctly for #2 is 98.25

  • Chemistry(Please Check) - ,

    1. My calculator reads 0.25941 which I would round to 0.259 and not 0.260. The reason you obtained 0.260 is because you rounded incorrectly for the first part of the question; i.e., 6.55/101 = 0.06485. If you round that off too much that makes all of the remaining answers that follow that wrong. This is what you should do.
    6.55/101 = some number BUT LEAVE THAT IN THE CALCULATOR. I don't even read the number and that saves some time. Then divide by 0.250L. That way you don't make rounding errors. ;-).

    2.
    The question is to find the number of mols in a 15.0 mL portion.
    mols = M x L = 0.0259M x 0.015L = ?

    3. 2.62 is correct but some profs get picky and will count off if you don't write the unit, also. I would write 2.62% m/v

    7. Now that you have #1, #7 follows:
    0.0259M x [250 mL/(250 mL + 1250 mL)] = ? or approximately 0.004 M

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