Posted by Liz on Monday, April 23, 2012 at 10:53am.
I found that it came to 6.30 for the pH. So I first balanced the equation set up an "ICE" box and then solved for x using the Ka equation...Ka=([H+][A-])/([HA]), I neglected the +x and -X and plugged in to solve. Then I got the pH by doing the negative log of the x. Hope this helped :)
I agree with 6.30 but I used the Henderson-Hasselbalch equation. It's easier and you don't need an ICE chart.
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