Math
posted by Sergio .
Determine whether the triangle has no/one/two solutions. Then Find and round measures of sides to the nearest tenth and measures of the angles to the nearest degree.
A= 50 degrees, a=34, b=40

sinA/a = sinB/b
sinB/40 = sin50°/34
sinB = 40sin50/34 = .901229
B = 64.32 or B = 115.68
Case1:
A = 50, B=64.32 , C = 65.68
c/sinC = a/sinA
c= 34sin65.68 /sin50 =40.445
case2:
A=50 , B = 115.68 C = 14.32°
c = 34sin14.32/sin50 = 10.98 = appr 11.0
Case1
A = 50° , B= 64° , C = 66°
a=34 , b=40 , c=40.4
Case2
A=50° , B= 116°, C= 14°
a=34, b=40 , c = 11.0