Posted by **Sergio** on Monday, April 23, 2012 at 1:08am.

Determine whether the triangle has no/one/two solutions. Then Find and round measures of sides to the nearest tenth and measures of the angles to the nearest degree.

A= 50 degrees, a=34, b=40

- Math -
**Reiny**, Monday, April 23, 2012 at 5:42am
sinA/a = sinB/b

sinB/40 = sin50°/34

sinB = 40sin50/34 = .901229

B = 64.32 or B = 115.68

Case1:

A = 50, B=64.32 , C = 65.68

c/sinC = a/sinA

c= 34sin65.68 /sin50 =40.445

case2:

A=50 , B = 115.68 C = 14.32°

c = 34sin14.32/sin50 = 10.98 = appr 11.0

Case1

A = 50° , B= 64° , C = 66°

a=34 , b=40 , c=40.4

Case2

A=50° , B= 116°, C= 14°

a=34, b=40 , c = 11.0

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