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Math

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Determine whether the triangle has no/one/two solutions. Then Find and round measures of sides to the nearest tenth and measures of the angles to the nearest degree.

A= 50 degrees, a=34, b=40

  • Math - ,

    sinA/a = sinB/b
    sinB/40 = sin50°/34
    sinB = 40sin50/34 = .901229
    B = 64.32 or B = 115.68

    Case1:
    A = 50, B=64.32 , C = 65.68
    c/sinC = a/sinA
    c= 34sin65.68 /sin50 =40.445

    case2:
    A=50 , B = 115.68 C = 14.32°

    c = 34sin14.32/sin50 = 10.98 = appr 11.0

    Case1
    A = 50° , B= 64° , C = 66°
    a=34 , b=40 , c=40.4

    Case2
    A=50° , B= 116°, C= 14°
    a=34, b=40 , c = 11.0

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