Posted by **Sergio ** on Monday, April 23, 2012 at 1:07am.

Determine whether the triangle has no/one/two solutions. Then Find and round measures of sides to the nearest tenth and measures of the angles to the nearest degree.

A= 50 degrees, a=34, b=40

- Math -
**Henry**, Tuesday, April 24, 2012 at 8:16pm
Given: A = 50 Deg., a = 34, b = 40.

sinB/b = sinA/a.

sinB/40 = sin50/34.

sinB = 40(sin50/34) = 0.9012.

B = 64 Deg.

C = 180 - A - B = 180 - 50 - 64=66 Deg.

c/sinC = a/sinA.

c/sin64 = 40/sin50.

c = sin64(40/sin50) = 46.9.

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