Math
posted by Sergio .
Determine whether the triangle has no/one/two solutions. Then Find and round measures of sides to the nearest tenth and measures of the angles to the nearest degree.
A= 50 degrees, a=34, b=40

Given: A = 50 Deg., a = 34, b = 40.
sinB/b = sinA/a.
sinB/40 = sin50/34.
sinB = 40(sin50/34) = 0.9012.
B = 64 Deg.
C = 180  A  B = 180  50  64=66 Deg.
c/sinC = a/sinA.
c/sin64 = 40/sin50.
c = sin64(40/sin50) = 46.9.