chemistry
posted by cateye .
following equilibrium system with a Kc of 1.23E03:
C3H6O (aq) + 2C2H6O (aq)> C7H16O2 (aq) + 2H2O (l)
1.What is the equilibrium expression for this system?
2.If the molar concentrations of C3H6O2 and C2H6O are both 0.255 at equilibrium, what is the equilibrium concentration of C7H16O2?

So write the equilibrium expression and substitute the numbers from the problem to evaluate Keq.

can you check to see I did it right.
1.[C3H6O][C2H6O]2/[C7H16O2]
2.2.04E06 
The Keq is not right. It's products/reactants with coefficients becoming exponents.
2 is also wrong because 1 is wrong. 
Plese check: thank u.
1.[C3H6O][C2H6O]2/[C7H16O2][H2O]2
2.8.00E05 
You wrote it the same way. Its products/reactants. Products are on the right. Reactants are on the left.
Keq = 1.23E3 = [C7H16O2]/[C3H6O][C2H6O]^2
and I omitted the water. Pure solids and pure liquids are not included.
8E5 is correct. 
The expression I wrote is correct.
The answer of #2 of 8E5 is not right. Neither you nor I squared the the term.
1.23E3 = x/(0.255)(0.255)^2 = and x = 2.04E5