Posted by maura on Sunday, April 22, 2012 at 10:28pm.
Suppose x=4sin(theta, for theta (pie/2, pie/2). Rewrite(sqrt16x^2)^3/x^3
(Sorry Im not very good at making symbols. I hope you know what I mean here! if not I can try to rewrite it a different way)

calculus  sabrina, Monday, April 23, 2012 at 1:01am
malachi has three tvs of: 25",27",32".
what the average size of malachi tvs?

calculus  Steve, Monday, April 23, 2012 at 10:15am
x = 4sinθ
sinθ = x/4
so, the other side is √(16x^2)
√(16x^2)/x = cotθ
[√(16x^2)/x]^3 = cot^3(θ)
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