Posted by **maura** on Sunday, April 22, 2012 at 10:28pm.

Suppose x=4sin(theta, for theta (-pie/2, pie/2). Rewrite(sqrt16-x^2)^3/x^3

(Sorry Im not very good at making symbols. I hope you know what I mean here! if not I can try to rewrite it a different way)

- calculus -
**sabrina**, Monday, April 23, 2012 at 1:01am
malachi has three tvs of: 25",27",32".

what the average size of malachi tvs?

- calculus -
**Steve**, Monday, April 23, 2012 at 10:15am
x = 4sinθ

sinθ = x/4

so, the other side is √(16-x^2)

√(16-x^2)/x = cotθ

[√(16-x^2)/x]^3 = cot^3(θ)

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