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Posted by on Sunday, April 22, 2012 at 10:28pm.

Suppose x=4sin(theta, for theta (-pie/2, pie/2). Rewrite(sqrt16-x^2)^3/x^3

(Sorry Im not very good at making symbols. I hope you know what I mean here! if not I can try to rewrite it a different way)

  • calculus - , Monday, April 23, 2012 at 1:01am

    malachi has three tvs of: 25",27",32".
    what the average size of malachi tvs?

  • calculus - , Monday, April 23, 2012 at 10:15am

    x = 4sinθ

    sinθ = x/4
    so, the other side is √(16-x^2)

    √(16-x^2)/x = cotθ

    [√(16-x^2)/x]^3 = cot^3(θ)

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