physics
posted by Akbar on .
A tire with an inner volume of 0.0250 m3 is filled with air at a gauge pressure of 30.3 psi. If the tire valve is opened to the atmosphere, what volume outside of the tire does the escaping air occupy? Some air remains within the tire occupying the original volume, but now that remaining air is at atmospheric pressure (14.7 psi). Assume the temperature of the air does not change.
m^3
I keep getting .0316m^3 but its wrong I don't know how to do this could someone help please. Thank you.

P1V1=P2V2
P1=30.3+atmpressure
P2= atmpressure
V1=.0250m^3
V2=EscapedV+.0250
put them in, and solve for EscapedV 
original pressure = 14.7 + 30.3 = 45 psi
p v = constant
45 * .0250 = 14.7 v
v = .0765
.0765  .0250 = .0500 m^3 
I suspect you used the "gage" pressure. No, bad.

Thank you both of you but both the methods I tried atill am getting it wrong :/...Damon I tried .0500m^3 and that was wrong and Bobpursley I tried your method i got 3.06 m^3 and still that's wrong too I don;t know why. Could someone please help me. Thank you!

Thank you Damon and Bobpursley. I really appreciate it.