Posted by Akbar on Sunday, April 22, 2012 at 8:01pm.
A tire with an inner volume of 0.0250 m3 is filled with air at a gauge pressure of 30.3 psi. If the tire valve is opened to the atmosphere, what volume outside of the tire does the escaping air occupy? Some air remains within the tire occupying the original volume, but now that remaining air is at atmospheric pressure (14.7 psi). Assume the temperature of the air does not change.
m^3
I keep getting .0316m^3 but its wrong I don't know how to do this could someone help please. Thank you.

physics  bobpursley, Sunday, April 22, 2012 at 8:41pm
P1V1=P2V2
P1=30.3+atmpressure
P2= atmpressure
V1=.0250m^3
V2=EscapedV+.0250
put them in, and solve for EscapedV

physics  Damon, Sunday, April 22, 2012 at 8:46pm
original pressure = 14.7 + 30.3 = 45 psi
p v = constant
45 * .0250 = 14.7 v
v = .0765
.0765  .0250 = .0500 m^3

physics  Damon, Sunday, April 22, 2012 at 8:47pm
I suspect you used the "gage" pressure. No, bad.

physics  Anonymous, Sunday, April 22, 2012 at 9:56pm
Thank you both of you but both the methods I tried atill am getting it wrong :/...Damon I tried .0500m^3 and that was wrong and Bobpursley I tried your method i got 3.06 m^3 and still that's wrong too I don;t know why. Could someone please help me. Thank you!

physics  Akbar, Monday, April 23, 2012 at 2:06pm
Thank you Damon and Bobpursley. I really appreciate it.
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