Posted by **emily** on Sunday, April 22, 2012 at 6:33pm.

can you please help me with this one

At serve, a tennis player aims to hit the ball horizontally.

part a)What minimum speed is required for the ball to clear the 0.90m--high net about 15.0m from the server if the ball is "launched" from a height of 2.50m ?

part b)here (relative to server) will the ball land if it just clears the net?

part c)Will it be "good" in the sense that it lands within 7.0m of the net? yes or no ?

part d) How long will it be in the air?

- I did this -
**Damon**, Sunday, April 22, 2012 at 6:37pm
Scroll down

- physics @ elena -
**Damon**, Sunday, April 22, 2012 at 6:38pm
Posted by clarissa on Sunday, April 22, 2012 at 6:03pm.

At serve, a tennis player aims to hit the ball horizontally.

part a)What minimum speed is required for the ball to clear the 0.90m--high net about 15.0m from the server if the ball is "launched" from a height of 2.50m ?

part b)here (relative to server) will the ball land if it just clears the net?

part c)Will it be "good" in the sense that it lands within 7.0m of the net? yes or no ?

part d) How long will it be in the air?

ap physics - Damon, Sunday, April 22, 2012 at 6:35pm

Hi = 2.5

h = .9

u = constant = 15/t

v = -g t

.9 = 2.5 + 0*t -4.9 t^2

so

t^2 = 1.6/4.9 = .3265

t = .5714 second

u = 15/t = 26.25 m/s

onward by yourself

- physics @ elena -
**emily**, Sunday, April 22, 2012 at 6:39pm
I saw that u aready did this, but when I calcuated everything my answers were still wrong

- physics @ elena -
**Damon**, Sunday, April 22, 2012 at 6:46pm
Sorry. I did it again and still got u = 26.25 m/s

- physics @ elena -
**Damon**, Sunday, April 22, 2012 at 6:49pm
To do the ground, repeat that calculation with h = 0 instead of .9

use the same u

part c, subtract 15 m

the way I did part b, you have t total

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