Posted by ####Nadine#### on Sunday, April 22, 2012 at 5:48pm.
Find the image distance from
1/do + 1/di = 1/f,
1/1.31 + 1/di = 1/(-125•10^-3).
di = - … (m) – virtual, in front of the length
The height of the image may be found from
M =h1/h2 = - di/do,
h1 = - … (inverted)
Thank you Elena, I had virtual and inverted also, but the book says it is virtual and upright. so I thought everything else was worry. Maybe it is the book?
Anybody's guess...
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