Janet jumps off a high diving platform with a horizontal velocity of 1.73 m/s and lands in the water 1.8 s later.

How high is the platform? The acceleration of gravity is 9.8 m/s2 .
Answer in units of m

no initial vertical speed

so
v = 0 -9.8 t
v at water = -9.8*1.8 = - 17.6 m/s

h = Hi + Vi t -4.9 t^2
0 = Hi + 0 -4.9(1.8)^2
Hi = 4.9* 1.8^2 = 15.9 m
(very high indeed)

The next part of the question is of course how far did Janet land from under the platform:
d = U t = 1.73 (1.8) = 3.11 m

I love you

Well, if Janet jumped off a high diving platform with a horizontal velocity of 1.73 m/s, we might need to notify the lifeguard about her unconventional diving technique first. But let's focus on the question at hand.

To find the height of the platform, we can use the equation of motion. The equation we'll be using is:

h = (1/2) * g * t^2

Where:
h = height of the platform
g = acceleration due to gravity (9.8 m/s^2)
t = time taken to reach the water (1.8 s)

Plugging in the values, we have:

h = (1/2) * 9.8 * (1.8)^2

Simplifying this, we get:

h = 0.5 * 9.8 * 3.24

h ≈ 15.876 m

So, the approximate height of the platform is 15.876 meters. Just remember, Janet might need a refresher on proper diving techniques before her next jump!

To find the height of the platform, we can use the kinematic equation:

h = v₀t + (1/2)gt²

where:
h = height of the platform
v₀ = initial horizontal velocity = 1.73 m/s
t = time taken to land = 1.8 s
g = acceleration due to gravity = 9.8 m/s²

Substituting the given values into the equation, we have:

h = (1.73 m/s)(1.8 s) + (1/2)(9.8 m/s²)(1.8 s)²

Simplifying this equation, we get:

h = 1.73 m + 1/2(9.8 m/s²)(1.8 s)²

h = 1.73 m + 1/2(9.8 m/s²)(3.24 s²)

h = 1.73 m + 44.604 m

h = 46.334 m

Therefore, the height of the platform is approximately 46.334 meters.

To determine the height of the platform, we can use the kinematic equation:

h = (v^2) / (2g)

Where:
h = height of the platform
v = horizontal velocity of the jump (1.73 m/s)
g = acceleration due to gravity (9.8 m/s^2)

First, let's calculate the vertical velocity (v_y) of Janet's jump. Since there is no vertical acceleration initially, the vertical velocity remains constant throughout the jump. We can use the formula:

v_y = g * t

Where:
v_y = vertical velocity
g = acceleration due to gravity (9.8 m/s^2)
t = time of flight (1.8 s)

v_y = 9.8 m/s^2 * 1.8 s
v_y = 17.64 m/s

Now, we can calculate the height of the platform using the formula mentioned earlier:

h = (v_y^2) / (2g)
h = (17.64 m/s)^2 / (2 * 9.8 m/s^2)
h ≈ 16.09 m

Therefore, the height of the platform is approximately 16.09 meters.