Posted by jason on Sunday, April 22, 2012 at 2:12pm.
A particle has a de Broglie wavelength of 3.30 1010 m. Then its kinetic energy quadruples. What is the particle's new de Broglie wavelength, assuming that relativistic effects can be ignored?

physics  Elena, Monday, April 23, 2012 at 3:26am
λ =h/p,
KE = p^2/2•m
p =sqrt(2•m•KE)
λ1 =h/sqrt(2•m•KE1),
λ2 =h/sqrt(2•m•KE2)=
= h/sqrt(2•m•4•KE1)=
= h/sqrt(4•p)= λ1/2 =
=1.65•10^10 m.