geometry
posted by punk480 on .
A circular pool with a diameter of 32 feet is surrounded by a wood deck of uniform width.
If the area of the deck is 68π square feet, what is x, the width of the deck?

x = r  16
pi (r^2  16^2) = 68 pi
so
r^2  16^2 = 68
r^2 = 324
r = 18
x = 1816 = 2 feet