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Calculate the enthalpy of the reaction
2B2H6 + 6O2=2B2O3 +6H2O

given the following pertinent information:
A. B2O3(s) + 2H2) )g) = 3O2 (g) + B2H6 (g), delta H= +2035kJ
B. 2B (s) + 3H2 (g) =B2H6 (g), delta H= +36 kJ
C. H2 (g) + 1/2)2 (g) =H2O (l), delta H=-285
D. H2O (l) = H2O (g), delta H=44

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