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January 29, 2015

January 29, 2015

Posted by **aj** on Sunday, April 22, 2012 at 1:27am.

- algebra -
**MathMate**, Sunday, April 22, 2012 at 10:10amSolve mentally:

Start with 6 dimes and 1 nickel.

The difference is $0.55.

To get $4.95 as the difference, we have to multiply by the factor $4.95/0.55=9

So there are 54 dimes and 9 nickels.

Solve by algebra:

N=number of nickels

D=6N=number of dimes

0.10D-0.05N=4.95

0.10(6N)-0.05N=4.95

0.55N=4.95

N=4.95/0.55=9 (as before)

D=6*9=54

- algebra -
**Kris**, Thursday, January 10, 2013 at 11:27pmJohn sister has $4.95 in dimes and quarters in her piggy bank. There are 3 fewer dimes than quarters. How many quarters and dimes are in the piggy bank?

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