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April 20, 2014

April 20, 2014

Posted by **Kimberly** on Saturday, April 21, 2012 at 8:58pm.

sin(A-B); tan A=12/5, A in quadrant 3, sinB=-3sqrt(10)/10, B in quadrant 4.

- Pre-Calculus -
**Reiny**, Saturday, April 21, 2012 at 9:36pmConstruct 2 triangles,

one in quad III for angle A with sides x=-5, y = -12 and r = 13

another in quad IV for angle B with sides x = √10 , y = 3√10 and r = 10

then sinA = -12/13, cosA = -5/13

sinB = 3√10/10 , cosB = √10/10

sin(A-B) = sinAcosB - cosAsinB

= (-12/13)(√10/10) - (-5/13)(-3√10/10)

= (-12√3 - 15√10)/130

= -27√10/130

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