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March 3, 2015

March 3, 2015

Posted by **John** on Saturday, April 21, 2012 at 7:42pm.

sin(è/2); tan è = − 5 / 12 , è in Quadrant IV

- pre-calc helpppp -
**Damon**, Saturday, April 21, 2012 at 7:59pm5^2+12^2 = h^2

25+144 = h^2 = 169

so hypotenuse = h = 13

sin e = -5/13

cos e = 12/13

sin(e/2) = -sqrt( [1-cos e] /2 )

sin(e/2) = -sqrt (1/13/2) = -sqrt(1/26)

- pre-calc helpppp -
**John**, Saturday, April 21, 2012 at 8:42pmThank you!!!!

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