Posted by **Jane** on Saturday, April 21, 2012 at 7:07pm.

The value of a $20,000 car decreases every, t. The equation below model this situation.

20,000(1-0.04t) = 13,000

How many years will the car be worth $13,000? Round to the nearest tenth if necessary.

I got 20,000(.96t)= 13,000, but I don't believe gives me the correct answer. Help!

- typo -
**Damon**, Saturday, April 21, 2012 at 8:26pm
this does not make sense:

" decreases every, t "

did it say it decreased 4% per year?

that would mean

.96^n =13/20

.96^n = .65

n log .96 = log .65

n = -.187/-.0177

= 10.6 years

- math -
**Jane**, Saturday, April 21, 2012 at 9:38pm
I understand most of the explanation except the part below:

n log .96 = log .65

n = -.187/-.0177

Could you please explain? Thanks

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