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March 28, 2017

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The value of a $20,000 car decreases every, t. The equation below model this situation.

20,000(1-0.04t) = 13,000

How many years will the car be worth $13,000? Round to the nearest tenth if necessary.

I got 20,000(.96t)= 13,000, but I don't believe gives me the correct answer. Help!

  • typo - ,

    this does not make sense:
    " decreases every, t "

    did it say it decreased 4% per year?
    that would mean
    .96^n =13/20
    .96^n = .65
    n log .96 = log .65
    n = -.187/-.0177
    = 10.6 years

  • math - ,

    I understand most of the explanation except the part below:

    n log .96 = log .65
    n = -.187/-.0177

    Could you please explain? Thanks

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