Posted by Lee on Saturday, April 21, 2012 at 6:50pm.
Convert pH 2.68 to (H^+) with
pH = -log(H^+).
Then HA --> H^+ + A^-
Ka = (H^+)(A^-)/(HA)
Substitute for (H^+) and (A^-). For (HA) substitute 0.0169-(H^+)
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