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February 27, 2015

February 27, 2015

Posted by **Stella** on Saturday, April 21, 2012 at 5:58pm.

- Algebra -
**Bosnian**, Saturday, April 21, 2012 at 6:03pma x ^ 2 + b x + c = a ( x - x1 ) ( x - x2 )

In this case :

x 1 = sq

- Algebra -
**Bosnian**, Saturday, April 21, 2012 at 6:28pma x ^ 2 + b x + c = a ( x - x1 ) ( x - x2 )

a leading coefficient

x1 and x2 roots

In this case :

x 1 = - sqrt ( 3)

x 2 = 3 sqrt ( 3 )

a x ^ 2 + b x + c = a [ ( x - ( - sqrt ( 3 ) ) ] * [ ( x - 3 sqrt ( 3 ) ) =

a [ ( x + sqrt ( 3 ) ) ] * [ ( x - 3 sqrt ( 3 ) ) =

a [ x * x + x * sqrt ( 3 ) - 3 sqrt ( 3 ) * x - 3 * sqrt ( 3 ) * sqrt ( 3 ) ] =

a [ x ^ 2 - 2 sqrt ( 3 ) x - 3 * 3 ] =

a [ x ^ 2 - 2 sqrt ( 3 ) x - 9 ]

a [ x ^ 2 - 2 sqrt ( 3 ) x - 9 ] = 0 Divide both sides by a

x ^ 2 - 2 sqrt ( 3 ) x - 9 = 0 / a

x ^ 2 - 2 sqrt ( 3 ) x - 9 = 0

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