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October 21, 2014

October 21, 2014

Posted by **Some1 Help Me Plz** on Saturday, April 21, 2012 at 3:26pm.

x-3)^2/9 + (y+2)^2/4<=1

and (x-3)^2+(y+2)^2>=4

I do not know how to simplify this down enough to graph it

- Inequalities -
**bobpursley**, Saturday, April 21, 2012 at 4:38pmThe first appears to be a all within a circle of radius 1, centered at (3,-2). Is that correct?

The second is a outside a circle of radius 2, centered at 3,-2

You do not need to simplify it, you need to RECOGNIZE a conic equation when you see one. Circle, parabola, hyperbola, and ellipse equations you should recognize those on sight. If you do not, get the standard forms on flashcards (they work) and MEMORIZE them.

- Inequalities -
**Some1 Help Me Plz**, Saturday, April 21, 2012 at 4:49pmI thought the first was an ellipse and the second was a circle

- Inequalities -
**Bosnian**, Saturday, April 21, 2012 at 5:07pmGo on: wolframalpha dot com

When page be open in rectangle type:

( x-3)^2/9 + (y+2)^2/4<=1 , (x-3)^2+(y+2)^2>=4

and click option =

After few seconds you will see everything about your inequalities,including graph.

- Inequalities -
**Some1 Help Me Plz**, Saturday, April 21, 2012 at 5:28pmThank you both so much.

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