Chemistry
posted by Katherine .
Calculate the concentrations of all species in a 0.810 M Na2SO3 (sodium sulfite) solution. The ionization constants for sulfurous acid are Ka1 = 1.4 x 10^2 and Ka2 = 6.3 x 10^8
I calculated SO32 = 0.8096 M, HSO3 = 3.58E4, H2SO3 = 7.1E13, OH = 3.58E4, H+ = 2.79E11
but i keep getting Na+ wrong!!! please help!

I think I answered this late last night that Na^+ = 2 x 0.810M = ?
Is that not right? 
Ohh.. I didn't know you were supposed to multiply the SO32 concentration by 2 for Na... That's right thanks DrBob!

Na2SO3 is 100% dissociated; therefore, Na2SO3 ==> 2Na^+ + SO3^2
So if Na2SO3 is 0.810M than Na^+ is twice that. You are multiplying the Na2SO3 by 2; not multiplying SO3^2 by 2. The SO3^2 is not 0.810 since it hydrolyzes (at least to a slight extent). 
What was your second chemical equation that you used?

If you have a question it would be best to post it under "Post a new question."