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September 23, 2014

September 23, 2014

Posted by **Al** on Saturday, April 21, 2012 at 5:29am.

- math -
**Reiny**, Saturday, April 21, 2012 at 8:31amMake a simple chart

....class A......class B

boys .. girls...boys .. girls

3y ...... 3x.......5y .... 2x

we know 3y+3x = 5y+2x

x = 2y

ration of girls to boys in class B

= 2x : 5y

= 2(2y) : 5y

**= 4 : 5**

There is no unique solution , just pick any value for y

e.g. using y = 5, then x = 10 (from x = 2y)

in the chart:

15.. 30....... 25 .. 20 satisfies the condition

y = 8, then x = 16

24 .. 48 ..... 40 .. 32 satisfies the condition

etc.

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