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January 31, 2015

January 31, 2015

Posted by **casidhe** on Friday, April 20, 2012 at 10:17pm.

Dimensions:

Minimum Perimeter:

- calculus -
**Reiny**, Friday, April 20, 2012 at 11:03pmlength -- x

width -- y

xy = 256

y = 256/x

perimeter = 2x + 2y

= 2x + 2(256/x) = 2x + 512/x

d(perimeter)/dx = 2 - 512/x^2

= 0 for a min of perimeter

2 = 512/x^2

x^2 = 256

x = √256 = 16

if x = 16, then y = 256/16 = 15

perimeter = 2(16)=2(16) = 64

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