How much heat (in Kj ) is required to warm 10.0g  of ice, initially at -11.0 C, to steam at 112.0 C?

q at a phase change = mass x heat vaporization for liquid to gas or

mass x heat fusion for solid to liquid.
For example, to change water from liquid at 100 C to steam at 100 C is mass H2O x heat vaporization.

q within a single phase is
mass x specific heat in that phase x (Tfinal-Tinitial).
For example, heat to raise T of water from liquid at zero C to liquid at 100 C is
mass H2O x specific heat H2O x (100)

To calculate the amount of heat required to warm a substance, you need to consider the following steps:

1. Find the heat required to warm the ice from -11.0°C to its melting point (0°C).
2. Find the heat required to melt the ice at its melting point.
3. Find the heat required to warm the water from 0°C to its boiling point (100°C).
4. Find the heat required to vaporize the water at its boiling point.
5. Find the heat required to warm the steam from the boiling point (100°C) to 112.0°C.
6. Sum up the heats obtained in steps 1 to 5 to get the total heat required.

First, let's calculate the heat required to warm the ice from -11.0°C to its melting point (0°C). The specific heat capacity of ice is 2.09 J/g°C.

Heat_1 = mass × specific heat × change in temperature
= 10.0g × 2.09 J/g°C × (0°C - (-11.0°C))
= 10.0g × 2.09 J/g°C × 11.0°C

Next, let's calculate the heat required to melt the ice. The heat of fusion of ice is 334 J/g.

Heat_2 = mass × heat of fusion
= 10.0g × 334 J/g

Now, let's calculate the heat required to warm the water from 0°C to its boiling point (100°C). The specific heat capacity of water is 4.18 J/g°C.

Heat_3 = mass × specific heat × change in temperature
= 10.0g × 4.18 J/g°C × (100.0°C - 0°C)

Then, let's calculate the heat required to vaporize the water at its boiling point. The heat of vaporization of water is 2260 J/g.

Heat_4 = mass × heat of vaporization
= 10.0g × 2260 J/g

Finally, let's calculate the heat required to warm the steam from the boiling point (100°C) to 112.0°C. The specific heat capacity of steam is 2.03 J/g°C.

Heat_5 = mass × specific heat × change in temperature
= 10.0g × 2.03 J/g°C × (112.0°C - 100.0°C)

Now, sum up all the heats obtained in the previous steps to get the total heat required.

Total Heat = Heat_1 + Heat_2 + Heat_3 + Heat_4 + Heat_5

After calculating the values, you will obtain the total heat in joules. To convert it to kilojoules (KJ), divide the total heat by 1000.

Total Heat (in KJ) = Total Heat (in J) / 1000

Hope this helps you to find the answer!