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April 19, 2015

April 19, 2015

Posted by **tabby** on Friday, April 20, 2012 at 7:41pm.

3 = r cos (theta - 315)

in rectangular form.

- Polar equations -
**ram**, Saturday, March 23, 2013 at 12:50am3=r cos(a-315)

where theta=a

now 315=360-45=2pi-pi/4=-pi/4

therefore, -315=+pi/4

therefore,3=r cos(a-315)becomes

3=r cos(a+pi/4)

but cos(a+pi/4)= cosa*cospi/4 - sina*sinpi/4

- Polar equations -
**ram**, Saturday, March 23, 2013 at 12:55am3=r cos(a-315)

where theta=a

now 315=360-45=2pi-pi/4=-pi/4

therefore, -315=+pi/4

therefore,3=r cos(a-315)becomes

3=r cos(a+pi/4)

but cos(a+pi/4)= cosa*cospi/4 - sina*sinpi/4

= 1/root2(cosa-sina)

3= 1/root2(rcosa-rsina)

= 1/root2 (x-y)

3root2=x-y

y = x-3root2 is an equation of line

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