Posted by tabby on Friday, April 20, 2012 at 7:41pm.
write the polar eqaution
3 = r cos (theta  315)
in rectangular form.

Polar equations  ram, Saturday, March 23, 2013 at 12:50am
3=r cos(a315)
where theta=a
now 315=36045=2pipi/4=pi/4
therefore, 315=+pi/4
therefore,3=r cos(a315)becomes
3=r cos(a+pi/4)
but cos(a+pi/4)= cosa*cospi/4  sina*sinpi/4

Polar equations  ram, Saturday, March 23, 2013 at 12:55am
3=r cos(a315)
where theta=a
now 315=36045=2pipi/4=pi/4
therefore, 315=+pi/4
therefore,3=r cos(a315)becomes
3=r cos(a+pi/4)
but cos(a+pi/4)= cosa*cospi/4  sina*sinpi/4
= 1/root2(cosasina)
3= 1/root2(rcosarsina)
= 1/root2 (xy)
3root2=xy
y = x3root2 is an equation of line
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