Homework Help: Polar equations

Posted by tabby on Friday, April 20, 2012 at 7:41pm.

write the polar eqaution
3 = r cos (theta - 315)
in rectangular form.

Polar equations - ram, Saturday, March 23, 2013 at 12:50am
3=r cos(a-315)
where theta=a
now 315=360-45=2pi-pi/4=-pi/4
therefore, -315=+pi/4
therefore,3=r cos(a-315)becomes
3=r cos(a+pi/4)
but cos(a+pi/4)= cosa*cospi/4 - sina*sinpi/4
Polar equations - ram, Saturday, March 23, 2013 at 12:55am
3=r cos(a-315)
where theta=a
now 315=360-45=2pi-pi/4=-pi/4
therefore, -315=+pi/4
therefore,3=r cos(a-315)becomes
3=r cos(a+pi/4)
but cos(a+pi/4)= cosa*cospi/4 - sina*sinpi/4
= 1/root2(cosa-sina)
3= 1/root2(rcosa-rsina)
= 1/root2 (x-y)
3root2=x-y
y = x-3root2 is an equation of line

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