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March 25, 2017

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A researcher wishes to estimate the proportion of college students who cheat on exams. A poll of 490 college students showed that 33% of them had, or intended to, cheat on examinations. Find the margin of error for the 95% confidence interval.

  • MATH##$$&&^^** - ,

    Margin of error = (1.96)[√(pq/n)]
    ...where p = .33, q = 1 - p, and n = 490

    Note: 1.96 represents 95% confidence interval.

    Plug the values into the formula and calculate.

    I let you take it from here.

  • MATH##$$&&^^** - ,

    4.16%

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