Posted by **Marie** on Friday, April 20, 2012 at 4:41pm.

Suppose that an object is thrown down towards the ground from the top of the 1100-ft tall Sears

Tower with an initial velocity of – 20 feet per second (the negative velocity indicates that the object

is moving towards the ground). Given that the acceleration due to gravity of the object is a constant –

32 feet per second per second, determine how far above the ground the object is exactly six seconds

after being thrown.

- Applied Calculus -
**Damon**, Friday, April 20, 2012 at 6:59pm
h = Hi + Vi t + (1/2) a t^2

Hi = 1100

Vi = - 20

a = -32

so

h = 1100 -20 t - 16 t^2

if t=6

h = 1100 -20*6 - 16*36

= 404 ft

- Applied Calculus -
**Damon**, Friday, April 20, 2012 at 7:02pm
all this from integrating acceleration

a = -32 ft/s^2

so

dv/dt = -32

v = Vi - 32 t

dh/dt = v = Vi - 32 t

h = Hi + Vi t - (1/2)(32)t^2

## Answer this Question

## Related Questions

- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...
- Algebra - THe function h(t)=-16t^2+v0t+h0 describes the height in feet above the...
- calculus - use a(t) = -32 ft per second squared as the acceleration due to ...
- algebra - y=(v/u)x+(g)/(2(u^2))*x^2 where y is the object's vertical distance (...
- Calculus - A ball is thrown straight down from the top of a 220-foot building ...
- calculus - Baseball Star Bryan is standing at the top of the Sears Tower in ...
- College Algebre - Here is the math problem: The height of an object in free fall...
- algebra - 5. 16t2 gives the distance in feet a free-falling object falls in t ...
- Physics - One object is thrown straight up at 54.9 m/s from the ground at the ...
- math - an object is thrown upward from the top of a 80-foot building with a ...

More Related Questions