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April 21, 2014

April 21, 2014

Posted by **Tabby** on Friday, April 20, 2012 at 3:54pm.

- Logarithms -
**bobpursley**, Friday, April 20, 2012 at 3:59pmtake the log of each side..

log6=(1-x)log15

log6/log15=1-x

x= 1-log6/log15

check that

- Logarithms -
**Tabby**, Friday, April 20, 2012 at 4:14pmthank you

- Logarithms -
**Anonymous**, Thursday, September 6, 2012 at 10:59amx2/y2

- Logarithms -
**2logx-3logy**, Thursday, September 6, 2012 at 11:01amx2/y2

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