I am not going to do all these
if y = u(x) v(x)
then dy/dx = u dv/dx + v du/dx
u = e^x so du/dx = e^x
v = sin^2 x so dv/dx = 2 sin x cos x
dy/dx = 2e^x sin x cos x + e^x sin^2 x
= e^x sin x ( 2 cos x + sin x)
Could you help me for these two:
b) y = (x²+1)e^-4
c) y = x²(e^Sinx)
Please & Thank you.
e^-4 is a constant
x^2 d/dx (e^sin x) + 2 x e^sin x
x^2 (e^sin x)cos x + 2 x e^sin x
x e^sin x [ x cos x + 2 ]
The answer for b) is e^-4(2x) ?
And everything after that is for c) right. So the final answer for c) would be xe^sinx(xcosx + 2)
In part c) for xcosx could you simplify that or do you keep it as xcosx? Thanks
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