Posted by **Amber** on Friday, April 20, 2012 at 12:41pm.

Consider a wheel (solid disk) of radius

0.748 m, mass 16 kg and moment of iner-

tia 1/2 MR^2 . The wheel rolls without slipping in a straight line in an uphill direction 27 above the horizontal. The wheel starts at

angular speed 20.5882 rad/s but the rotation slows down as the wheel rolls uphill, and eventually the wheel comes to a stop and rolls back downhill.How far does the wheel roll in the uphill

direction before it stops? The acceleration of gravity is 9.8 m/s^2 .

Answer in units of m

- Physics. PLEASE HELP!! -
**Elena**, Friday, April 20, 2012 at 6:10pm
KE = PE,

KE = mv^2/2 + Iω^2/2 =m• (ω•R)^2/2 = m•R^2• ω^2/4 = 3• m•R^2• ω^2/4,

PE = m•g•h = m•g•s•sinα,

3• m•R^2• ω^2/4 = m•g•s•sinα,

s =3•R^2• ω^2/4•g•sinα.

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