Posted by Amber on Friday, April 20, 2012 at 12:37pm.
To stop the wheel, the tangential force will have to do an
amount of work equal to the initial rotational kinetic energy of the wheel.
ω =2•π•n = 2• π•950/60 rad/s
W = I•ω^2/2 = m•R^2• ω^2/4,
where ω =2•π•n = 2• π•950/60 rad/s.
The tangential force and the distance d = 0.5 m are unnecessary for calculation.
a rocket initially at rest on the ground lifts off vertically with a constant acceleration of 2.0 X 10^4 meter per second squared. How long will it take the rocket to reach an altitude of 9.0 X 10^3 meter?
a rocket initially at rest on the ground lifts off vertically with a constant acceleration of 2.0 X 10^4 meter per second squared. How long will it take the rocket to reach an altitude of 9.0 X 10^3 meter?
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