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September 16, 2014

September 16, 2014

Posted by **ali** on Friday, April 20, 2012 at 7:55am.

a.50N b.13N c.17N d.25N

- physics -
**Henry**, Saturday, April 21, 2012 at 9:19pmWb = mg = 5kg * 9.8N/kg = 49 N.

Fb = 49N @ 0 Deg. = Force of box.

Fp = 49*sin(0) = 0. = Force parallel to

floor.

Fv = 49*cos(0) = 49 N. = Force perpendicular to floor.

Fv'=Fv-Fap*sin37 = 49-40sin37 = 24.9 N.

= Normal. = Net force perpendicular to

floor.

Fn = Fap*cosA-Fp-Fk = ma.

40*cos37-0-Fk = 5*3.

31.9 - Fk = 15.

Fk = 31.9 - 15 = 17.N. = Force of kinetic friction.

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