February 20, 2017

Homework Help: Chemistry

Posted by Katherine on Friday, April 20, 2012 at 1:46am.

C6H5COOH(aq) + NO2-(aq) <=> C6H5COO-(aq) + HNO2(aq)

A table of ionizations is given to calculate the equilibrium constant for this overall reaction.. but when i looked onto the table the only thing given was the Ka for C6H5COOH [6.3×10^–5] and HNO2 [5.6×10^–4]

it doesn't show me the Ka for NO2- or C6H5COO- ... is there a way I can solve K without knowing the Ka for those last two..? please help! it'll be greatly appreciated!

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