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March 5, 2015

March 5, 2015

Posted by **Cindy** on Friday, April 20, 2012 at 1:45am.

Thank you in advance ^^

- Math/ Algebra 2 -
**Reiny**, Friday, April 20, 2012 at 7:56amSince the first and last are fixed, that leaves you with the letters

OMBINATION , I see two I's and two O's

number of arrangements of these

= 10!/(2!2!) = 907200

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