Posted by Josh on .
sin^4tcos^4t/sin^2t cos^2t= sec^2tcsc^2t
i have =(sin^2t+cos^2t)(sin^2t+cos^2t)/sin^2tcos^2t
then do i go =(sin^2t+cos^2t)/sin^2tcos^2t
stumped

Trig 
Reiny,
LS = (sin^2 t + cos^2 t)(sin^2 t  cos^2 t)/(sin^2 t cos^2 t)
= 1(sin^2 t  cos^2 t)/(sin^2 t cos^2 t)
= sin^2 t/(sin^2 t cos^2 t)  cos^2 t/(sin^2 t cos^2 t)
= 1/cos^2 t  1/sin^2 t
= sec^2 t  csc^2 t
= RS