Homework Help: Chemistry

Posted by Raskin on Thursday, April 19, 2012 at 7:40pm.

Deriving Chem Beer's Law's Equation
By comparing the absorbance of each trial solution, Aeq, to the absorbance of the standard solution, Astd, [FeNCS2+]eq can be determined. Two Beer’s Law equations can be written, one for the trial (Aeq = ε[FeNCS2+]eql), one for the standard (Astd = ε[FeNCS2+]stdl).

Set these two equations equal to each other to derive equation (2).

Note : the "l" is a special symbol as well
The derived equation looks like this : [FeNCS2+]eq = Aeq / Astd *[FeNCS2+]std

I'm having trouble deriving it myself? Any tips or help would greatly be appreciated!

Chemistry - DrBob222, Thursday, April 19, 2012 at 9:10pm
The hint tells you how to do it. Set the two equations equal to each other and solve for [FeNCS2+]eq.
Chemistry - Anonymous, Thursday, April 19, 2012 at 9:46pm
I don't understand how its Aeq / Astd * [FeNCS2+]std

What am I setting equal exactly?
ε[FeNCS2+]eql)/Aeq = ε[FeNCS2+]stdl/Astd ?
Chemistry - Anonymous, Friday, April 20, 2012 at 12:40am
solve for the epsilon and then plug them in.

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