Posted by **Taurus** on Thursday, April 19, 2012 at 2:25pm.

I am not understanding these kinds of problems: I cannot simplify with understanding.

7 times the 4th root of m^3 plus 9 times the 4th root of 256m^3.

- Algebra -
**Tulika**, Thursday, April 19, 2012 at 2:39pm
it can also be written as:

7 x [m^(3/4)] + 9[256m^(3/4)]

solve it

- Algebra -
**Steve**, Thursday, April 19, 2012 at 4:48pm
a correction is in order, as it should be

7 x [m^(3/4)] + 9[(256m^3)^(1/4)]

= 7∜m^3 + 9(∜256∜m^3)

= 7∜m^3 + 9(4∜m^3)

= 43∜m^3

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