Posted by Amanda on Thursday, April 19, 2012 at 12:22pm.
in QIII, sin and cos are both negative.
You have a 5-12-13 triangle, so
sinA = -12/13
cosA = -5/13
in QIV, cos is positive.
You have a 3-1-√10 triangle, so
cosB = 1/√10
Now apply the addition formula
sin(A+B) = sinAcosB + cosAsinB
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