Posted by **Fakaapo. Suetusi** on Thursday, April 19, 2012 at 10:17am.

Maria is playing a game of chance at the Hibiscus festival, costing $1 for each game. In the game two fair dice are rolled and the sum of the numbers that turn up is found. If the sum is seven, then Maria wins $5. Otherwise Maria loses her money.

a) Please can you Construct Maria’s probability distribution for gaining.

Thank you for your help.

- Please can you help me (Probability) -
**MathMate**, Thursday, April 19, 2012 at 10:39am
There are 36 possible outcomes which can be grouped into 11 events E represented by the totals of 2 to 12, each with probability P(E).

For example construct the probability distribution table:

E P(E)

2 1/36 (only one way to make a sum of 2)

3 2/36 (two ways to make a sum of 3)

4 3/36 (3 ways to make 4: 1+3,2+2,3+1)

...

12 1/36

The gain for each event is G(E)= -1 except for E=7 where the gain is G(7)=5.

The expected gain is ∑G(E)P(E) for all E.

## Answer this Question

## Related Questions

Math - Maria is playing a game of chance at the Hibiscus festival, costing $1 ...

Math - At this year's State Fair, there was a dice rolling game. If you rolled ...

Statistics - In a game you roll two fair dice. If the sum of the two numbers ...

biology - One rule of probability can be expressed as the following: The ...

biology - One rule of probability can be expressed as the following: The ...

Math - Suppose you play a game in which two fair standard dice are rolled. If ...

Math - The game of dots is played by rolling a fair dice and receiving $1 for ...

math - For a carnival game, a cube is rolled.Each of its six faces has a ...

statistics - A friend offers you the following game: You will roll 2 fair dice. ...

Math- Alg 2 - Help finding probability involving combinations? What is the ...