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October 25, 2014

October 25, 2014

Posted by **Fakaapo. Suetusi** on Thursday, April 19, 2012 at 10:17am.

a) Please can you Construct Maria’s probability distribution for gaining.

Thank you for your help.

- Please can you help me (Probability) -
**MathMate**, Thursday, April 19, 2012 at 10:39amThere are 36 possible outcomes which can be grouped into 11 events E represented by the totals of 2 to 12, each with probability P(E).

For example construct the probability distribution table:

E P(E)

2 1/36 (only one way to make a sum of 2)

3 2/36 (two ways to make a sum of 3)

4 3/36 (3 ways to make 4: 1+3,2+2,3+1)

...

12 1/36

The gain for each event is G(E)= -1 except for E=7 where the gain is G(7)=5.

The expected gain is ∑G(E)P(E) for all E.

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