Posted by Al on Thursday, April 19, 2012 at 12:03am.
Sasa had some 20-cent and 50-cent coins.
7/8 of the coins were 20-cent coins and the rest were 50-cent coins.After Sasa had spent $72.50 worth of 50-cent coins and 5/7 of the 20-cent coins, she had 2/7 of the coins left. Find the total amount of money Sasa left.
- math - Steve, Thursday, April 19, 2012 at 12:12pm
let there be:
t 20¢ coins
f 50¢ coins
7/8 c = t
1/8 c = f
so, t = 7f
72.50 is 145 of the 50¢ coins
(f + t) - 145 - (5/7 t) = 2/7 (f+t)
since t = 7f,
f + 7f - 145 - 5f = 2/7 * 8f
f = 203
so, t = 1421
and 1624 coins in all
1624 - 145 - 5/7 (1421)
= 1624 - 145 - 1015
464 is 2/7 of 1624
- math - Al, Thursday, April 19, 2012 at 10:03pm
Thank you, Steve.
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