Posted by **Al** on Thursday, April 19, 2012 at 12:03am.

Sasa had some 20-cent and 50-cent coins.

7/8 of the coins were 20-cent coins and the rest were 50-cent coins.After Sasa had spent $72.50 worth of 50-cent coins and 5/7 of the 20-cent coins, she had 2/7 of the coins left. Find the total amount of money Sasa left.

- math -
**Steve**, Thursday, April 19, 2012 at 12:12pm
let there be:

c coins

t 20¢ coins

f 50¢ coins

7/8 c = t

1/8 c = f

so, t = 7f

72.50 is 145 of the 50¢ coins

(f + t) - 145 - (5/7 t) = 2/7 (f+t)

since t = 7f,

f + 7f - 145 - 5f = 2/7 * 8f

f = 203

so, t = 1421

and 1624 coins in all

check:

1624 - 145 - 5/7 (1421)

= 1624 - 145 - 1015

= 464

464 is 2/7 of 1624

- math -
**Al**, Thursday, April 19, 2012 at 10:03pm
Thank you, Steve.

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